A JSP can be used with an HTML form tag to allow users to upload
files to the server. An uploaded file could be a text file or binary or
image file or any document.
Creating a File Upload Form:
The following HTM code below creates an uploader form. Following are the important points to be noted down:
The form method attribute should be set to POST method and GET method can not be used.
The form enctype attribute should be set to multipart/form-data.
The form action attribute should be set to a JSP file which would handle file uploading at backend server. Following example is using uploadFile.jsp program file to upload file.
To upload a single file you should use a single <input
.../> tag with attribute type="file". To allow multiple files
uploading, include more than one input tags with different values for
the name attribute. The browser associates a Browse button with each of
them.
<html><head><title>File Uploading Form</title></head><body><h3>File Upload:</h3>
Select a file to upload: <br/><formaction="UploadServlet"method="post"enctype="multipart/form-data"><inputtype="file"name="file"size="50"/><br/><inputtype="submit"value="Upload File"/></form></body></html>
This will display following result which would allow to select a file
from local PC and when user would click at "Upload File", form would be
submitted along with the selected file:
FileUpload:Select a file to upload:
NOTE: Above form is just dummy form and would not work, you should try above code at your machine to make it work.
Writing Backend JSP Script:
First let us define a location where uploaded files would be stored.
You can hard code this in your program or this directory name could
also be added using an external configuration such as a context-param element in web.xml as follows:
<web-app>
....
<context-param><description>Location to store uploaded file</description><param-name>file-upload</param-name><param-value>
c:\apache-tomcat-5.5.29\webapps\data\
</param-value></context-param>
....
</web-app>
Following is the source code for UploadFile.jsp which can handle
multiple file uploading at a time. Before procedding you have make sure
the followings:
Following example depends on FileUpload, so make sure you have the latest version of commons-fileupload.x.x.jar file in your classpath. You can download it from http://commons.apache.org/fileupload/.
FileUpload depends on Commons IO, so make sure you have the latest version of commons-io-x.x.jar file in your classpath. You can download it from http://commons.apache.org/io/.
While testing following example, you should upload a file which has less size than maxFileSize otherwise file would not be uploaded.
Make sure you have created directories c:\temp and c:\apache-tomcat-5.5.29\webapps\data well in advance.
<%@ page import="java.io.*,java.util.*, javax.servlet.*" %>
<%@ page import="javax.servlet.http.*" %>
<%@ page import="org.apache.commons.fileupload.*" %>
<%@ page import="org.apache.commons.fileupload.disk.*" %>
<%@ page import="org.apache.commons.fileupload.servlet.*" %>
<%@ page import="org.apache.commons.io.output.*" %>
<%File file ;int maxFileSize =5000*1024;int maxMemSize =5000*1024;ServletContext context = pageContext.getServletContext();String filePath = context.getInitParameter("file-upload");// Verify the content typeString contentType = request.getContentType();if((contentType.indexOf("multipart/form-data")>=0)){DiskFileItemFactory factory =newDiskFileItemFactory();// maximum size that will be stored in memory
factory.setSizeThreshold(maxMemSize);// Location to save data that is larger than maxMemSize.
factory.setRepository(newFile("c:\\temp"));// Create a new file upload handlerServletFileUpload upload =newServletFileUpload(factory);// maximum file size to be uploaded.
upload.setSizeMax( maxFileSize );try{// Parse the request to get file items.List fileItems = upload.parseRequest(request);// Process the uploaded file itemsIterator i = fileItems.iterator();out.println("<html>");out.println("<head>");out.println("<title>JSP File upload</title>");out.println("</head>");out.println("<body>");while( i.hasNext ()){FileItemfi=(FileItem)i.next();if(!fi.isFormField ()){// Get the uploaded file parametersString fieldName =fi.getFieldName();String fileName =fi.getName();boolean isInMemory =fi.isInMemory();long sizeInBytes =fi.getSize();// Write the fileif( fileName.lastIndexOf("\\")>=0){
file =newFile( filePath +
fileName.substring( fileName.lastIndexOf("\\")));}else{
file =newFile( filePath +
fileName.substring(fileName.lastIndexOf("\\")+1));}fi.write( file );out.println("Uploaded Filename: "+ filePath +
fileName +"<br>");}}out.println("</body>");out.println("</html>");}catch(Exception ex){System.out.println(ex);}}else{out.println("<html>");out.println("<head>");out.println("<title>Servlet upload</title>");out.println("</head>");out.println("<body>");out.println("<p>No file uploaded</p>");out.println("</body>");out.println("</html>");}
%>
Now try to upload files using the HTML form which you created above.
When you would try http://localhost:8080/UploadFile.htm, it would
display following result which would help you uploading any file from
your local machine.
FileUpload:Select a file to upload:
If your JSP script works fine, your file should be uploaded in c:\apache-tomcat-5.5.29\webapps\data\ directory.
Không có nhận xét nào:
Đăng nhận xét